PLEASE HELP Triangle XYZ has its vertices at the following coordinates: X(2, 1) Y(4,-1) Z(1,-3)

Give the coordinates of the image triangle X'Y'Z' after a 90° counterclockwise rotation about the origin.

solved

Step-by-step explanation:

Let , the points are X(x_1,y_1)\ ,Y(x_2,y_2) \ , Z(x_3,y_3)X(x

1

,y

1

) ,Y(x

2

,y

2

) ,Z(x

3

,y

3

) .

When any point ( h , k ) is rotated 90° counterclockwise about the origin the new point produced is ( -k , h).

So , applying same concept in XYZ :

X'(-y_1,x_1)\ ,Y'(-y_2,x_2) \ , Z'(-y_3,x_3)X

′

(−y

1

,x

1

) ,Y

′

(−y

2

,x

2

) ,Z

′

(−y

3

,x

3

) .

Therefore , transformed points are X'(-y_1,x_1)\ ,Y'(-y_2,x_2) \ , Z'(-y_3,x_3)X

′

(−y

1

,x

1

) ,Y

′

(−y

2

,x

2

) ,Z

′

(−y

3

,x

3

) .

Hence , this is the required solution

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of