Can someone please help me thank you

(x+1)(x+2)(x-3)

x³-7x-6

Step-by-step explanation:

We are looking for an equation where we have a degree of 3 and where we can plug in -1, -2, or 3 for x and have it equal 0

the first one is definetly correct

To see if there's another answer let's mulitply it out

(x+1)(x+2)(x-3)= (x-3)(x²+3x+2)= x³-7x-6 which is equal to the third one

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

it's a proportional graph.

step-by-step explanation:

8 x 5 = 40         (and you have -8x and -5y)

x= absiss

y= orderly

so you have a proportional graph.