In an arithmetic sequence, if a2=5 and a10=19 find a6

93

Step-by-step explanation: The first term of AP is -5 and second term means -3.  

Common difference(d) = second term - first term

d = (-3)-(-5)

d= 2

Now using the formula of nth T  

n

=a  

1

+(n−1)d

Here a  

1

=−5,n=50,d=2

Puting these values in the formula of of nth term we get  

a  

n

=−5+(50−1)2

a  

n

=−5+98

a  

n

=93

i believe the answer is d.

hope it you! : d

1.3 million hoops i believe