What is the smallest number by which 9408 must be divided so that the quotient is perfect cube?

Out of the prime factors of 9408, only 3 is without pair. So, 3 is the number by which 9408 must be divided to make the quotient a perfect square.

Step-by-step explanation:

To find the smallest number by which 9408 must be divided so that the quotient is a perfect square, we have to find the prime factors of 9408.

9408 = 2*2*2*2*2*2*3*7*7

Prime factors of 9408 are 2, 2, 2, 2, 2, 2. 3, 7, 7

Out of the prime factors of 9408, only 3 is without pair.

So, 3 is the number by which 9408 must be divided to make the quotient a perfect square.

9408/3 = 3136

Square root of 3136

             56

  5   |    3136

  5   |    25

___  |

106  |      636

  6   |      636

       |

       |      000

So, √3136 = 56

Answer.              

d 600 because 15*10*2=300

300+300=600

step-by-step explanation: