Use
S=n2 to find the sum of 1+3+5+. . . + 301.

I'm not sure what the question means by "use S = n^2"...

At any rate, the given sum

1 + 3 + 5 + … + 301

is simply the sum of the first 151 odd positive integers, which we can write in the form 2n - 1 for n between 1 and 151. That is,

We can expand the sum as

Next, recalling that

it follows that

(Probably "S = n^2" means "sum of n odd integers = n ²")

step-by-step explanation:

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube