A cyclist is moving at a velocity of 6m/s and decelerates at a constant rate of 4m. What is the value of the cyclist's acceleration. v^2-u^2=2ax

no this is a nonlinear negative

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4

16 would be your answer

i believe your answer is a