If a rock falls from a height of 44 meters on Earth, the height H (in meters) after x seconds is approximately H(x) = 44 - 4.9x². (a) What is the height of the rock when x = 1.3 seconds?
meters.
The height of the rock when x = 1.3 seconds is
(Round to three decimal places as needed.)
(b) When is the height of the rock 13 meters?
seconds
The height of the rock is 13 meters when x
(Round to two decimal places as needed.)
(c) When does the rock strike the ground?
The rock strikes the ground when x seconds.
(Round to two decimal places as needed.)

3,000,540

step-by-step explanation:

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)