One solution each is given for four quadratic equations. Assuming that each quadratic equation has two solutions, what is the second solution for each equation? arrowRight

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goog may be able to you find that answer

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

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y

=

−

2

find the upper bound of the range.

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y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

i am not sure :

step-by-step explanation:

the answer would be a 24

step-by-step explanation:

c=2πr=2·π·3=24