the length of the rectangle is 5 yards more than twice the width and the area of the rectangle is 63 yards squared what is the length what is the width

Step-by-step explanation:

L = 2W + 5

A = LW = 63

L = 63/W

W=63/L

L = 2W + 5

63/W = 2W + 5

63 = 2WW + 5W

2WW + 5W - 63 = 0

2WW + 5W - 63 = 0

is already in quadratic equation form: ax^2 + bx + c = 0

use the quadratic formula to solve for two solutions:

x = ( -b +- sqrt( bb - 4ac ) ) / 2a

the two solutions are:

x = 9/2

x = -7

you cant have a negative solution for length so use the positive one

solve for length:

L=5+2(9/2)

L=5+18/2

L=5+9

L=14

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4

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step-by-step explanation:

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