ANYONE PLEASE HELP ME WITH MY HOMEWORK BECAUSE I HAVE TO PASS IT LATER I HOPE Y’ALL CAN HELP ME:( I’LL MARK BRAINLIEST FOR THOSE WHO CAN ANSWER IT CORRECTLY!

3% decrease / decay

Step-by-step explanation:

I could be wrong but I really hope it isn't! Hope this helps out if you need A step-by-step let me know in the comments! ^^

-I  can't do it I even goobled it, just delete my answer so you can get proper help from someone else ;u; so sorry I wasn't much of a help and I bid thee good luck!

i wish i could u

step-by-step explanation:

i wish i could u

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.