The domain of the function f(x)=4/(4x+16) is all real numbers except for when x equals___

-4

Step-by-step explanation:

f(x)= 4/4x+16

reduce denominator to find the vertical asymptote

4/4(x+4)

Now what makes x equal to zero?

x+4=0

x=-4

So if I were to plug in -4 it'd give me 0

As you can see in the graph the function will never approach x at -4

Also although not asked this function is just 4/4(x+4)

since u cancel the 4s

1/x+4

he kicked it up? is this the answer ?

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92