The family of this graph?

Step-by-step explanation:

The shape of this graph is that of a parabola.  In this case the parabola opens down.  The general form of the equation of such a parabola is

y = a(x - h)^2 + k, where (h, k) is the vertex and a is a coefficient to be determined.

In this particular case we can obtain the coordinates of the vertex (h, k) from the graph.  They are (3, 4).  Thus, h = 3 and k = 4.  The graph goes through (1.5, 0).  Use this information to determine the value of the coefficient a:

Then the equation of this parabola must be y = a(x - 3)^2 + 4.

0 = a(1.5 - 3)^2 + 4

Then:

0 = a(-1.5)^2 + 4, or

0 = 2.25a + 4, or

2.25a = -4, or

a = 16/9

Thus, the final result:  The equation of this parabola is

y = (16/9)(x - 3)^2 + 4

whose graph is a parabola that opens down and has vertex (3, 4).            

how am i supposed to answer

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form