Help ASAP! Plz
Find the indicated angle
measure.

21. <ABC = 58 Degrees

22. <LMN = 108 Degrees

23. <RSV = 42 Degrees

24. <LHK = 101 Degrees

28. <ABX = 112 Degrees and <CBX = 68 Degrees

29. <RSQ = 32 Degrees and <TSQ = 58 Degrees

30. <DEH = 39 Degrees and <FEH = 51 Degrees

Step-by-step explanation:

21. Add the degrees the find angle ABC

37 + 21 = 58

22. Add the degrees the find angle LMN

85 + 23 = 108

23. For this problem, you are suppose to subtract the angle measure given to you (72 degrees) from the degrees of the whole angle (<RST) to find the missing angle (RSV)

114 - 72 = 42

24. GHK is a straight line, meaning it equals 180 degrees. Subtract 180 from the angle measure given (79) to find the missing angle (LHK).

180 - 79 = 101

28. ABC is a straight line, meaning it equals 180 degrees. This also means that ABX + CBX = 180. First, find x, then use x to find the measures of ABX and CBX.

(14x + 70) + (20x + 8) = 180

Add Like Terms

34x + 78 = 180

Subtraction Prop. of Eq.

34x = 102

x = 3

Now, you can find the angle measures

14 * 3 + 70 = 112

20 * 3 + 8 = 68

(Make sure to check your work! 112 + 68 does indeed equal 180!)

29. RST is a right angle, meaning it equals 90 degrees. This also means that RSQ + TSQ = 90. First, find x, then use x to find the measures of RSQ and TSQ.

(15x - 43) + (8x + 18) = 90

Add Like Terms

23x - 25 = 90

Addition Prop of Eq.

23x = 115

x = 5

Now, you can find the angle measures

15 * 5 - 43 = 32

8 * 5 + 18 = 58

(Make sure to check your work! 32 + 58 does indeed equal 90!)

30. DEF is once again a right angle, so we follow the same steps from number 29.

13x + (10x + 21) = 90

Add Like Terms

23x + 21 = 90

Subtraction Prop of Eq.

23x = 69

x = 3

Now, you can find the angle measures

13 * 3 = 39

10 * 3 + 21 = 51

(Make sure to check your work! 39 + 51 does indeed equal 90!)

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm