The probability that a randomly chosen player will train offense is 1/2; the probability of a randomly chosen player will train defense is 8/11; the probability of a randomly chosen player will train on both is 4/11. Let A be the event that a player will train on offense and B be the event that a player will train on defense. Are events A and B mutually exclusive, independent, both, or neither?

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step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

b

step-by-step explanation:

multiply terms on numerator/ denominator by (x - 1)

= ← distribute numerator/ denominator

= ← simplify

=

= → b