What is 72 - 2y^2 fully factorised

2 * (6-y) * (6+y)

Step-by-step explanation:

72 - 2 * y^2 = 2 * (36 - y^2) = 2 * (6-y) * (6+y)

so it's 2 * (6-y) * (6+y)

its 2(6-y).(6+y)

firstly you factor out 2from the expression

from 72-2y^2 to 2(36-y^2)

then you use a^2-b^2=(a-b) (a+b) and we factor the expression

2(6-y).(6+y)

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v