I JUST WANNA CHECK IF ITS CORRECT !!

I got the one above it: L=-w

Step-by-step explanation:

To solve "P= 2(L+W)" , first distribute:

P= 2L+2W

Then get "2L" alone (by subtracting 2W from both sides):

P-2W= 2L-------- 2L= P-2W

Then divide by two to get just "L":

L= -W

Hope this helps!

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)