To get a c in history, Nandan must average 72 on four tests. Scores on the first three tests were 65, 77, and 60. What is the lowest score Nandan can get on the last test and still receive a c?

Step-by-step explanation:

average means the sum of all events divided by the number of events.

so, (65 + 77 + 60 + x)/4 >= 72

we solve for x and = 72.

65+77+60+x = 288

x = 86

so, he must score at least a 86.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

3,000,540

step-by-step explanation: