![2 {p}^{ \frac{1}{3} } = 6 \\ 2 \sqrt[3]{p} = 6 \\ \\ \sqrt[3]{p} = \frac{6}{2} \\ \\ \sqrt[3]{p} = 3 \\ \\( {p}^{ \frac{1}{3} }) ^{3} = {(3)}^{3} \\ \\ p = {3}^{3} \\ \\ p = 27](/tpl/images/2490/1931/4fdf9.png)
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