у do Which interval for the graphed function has a local minimum of 0? 4 (1-2, 291 O [-3, -2] O [-2, 0] O [1, 2] [2, 4] ON [(-2.5, 9) (0,0) 2 (3,0) 4 X 6- (-1.56,6) -8

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

i dont get the question

step-by-step explanation:

if you was gonna solve for a, a is a   < -12

21

jk it's 20

step-by-step explanation: