![\rm :\longmapsto\:\rm \: {(3x)}^{2} + \bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15 \bigg)x + 4 = 0](/tpl/images/2491/0431/0d468.png)
![\rm :\longmapsto\:\rm \: {9x}^{2} + \bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15 \bigg)x + 4 = 0](/tpl/images/2491/0431/f0edc.png)
![\red{\rm :\longmapsto\:b = 27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15}](/tpl/images/2491/0431/0288f.png)
![\rm :\longmapsto\: {\bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15\bigg)}^{2} - 4 \times 4 \times 9 = 0](/tpl/images/2491/0431/6f30f.png)
![\rm :\longmapsto\: {\bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15\bigg)}^{2} - 144 = 0](/tpl/images/2491/0431/814c0.png)
![\rm :\longmapsto\: {\bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15\bigg)}^{2} = 144](/tpl/images/2491/0431/f09a5.png)
![\rm :\longmapsto\: {\bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15\bigg)}^{2} = {12}^{2}](/tpl/images/2491/0431/ce2a0.png)
![\rm \implies\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15 = \: \pm \: 12](/tpl/images/2491/0431/33bb2.png)
![\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15 = - 12](/tpl/images/2491/0431/22134.png)
![\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } = - 12 + 15](/tpl/images/2491/0431/c7dda.png)
![\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } = 3](/tpl/images/2491/0431/82fa5.png)
![\rm \implies\:{\bigg[3\bigg]}^{ \dfrac{1}{k} } = \dfrac{1}{9}](/tpl/images/2491/0431/141a3.png)
![\rm \implies\:{\bigg[3\bigg]}^{ \dfrac{1}{k} } = \dfrac{1}{ {3}^{2} }](/tpl/images/2491/0431/11c74.png)
![\rm \implies\:{\bigg[3\bigg]}^{ \dfrac{1}{k} } = {3}^{ - 2}](/tpl/images/2491/0431/a0620.png)
![\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15 = 12](/tpl/images/2491/0431/0cc70.png)
![\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } = 12 + 15](/tpl/images/2491/0431/a6f13.png)
![\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } = 27](/tpl/images/2491/0431/1e394.png)
![\rm :\longmapsto\: {\bigg[3\bigg]}^{ \dfrac{1}{k} } = 1](/tpl/images/2491/0431/881bd.png)
![\rm :\longmapsto\: {\bigg[3\bigg]}^{ \dfrac{1}{k} } = {3}^{0}](/tpl/images/2491/0431/64081.png)
If the equation;
(3x)² + {27 × (3)^1/k - 15}x + 4 = 0
has equal roots find k
...
Mathematics, 05.10.2021 14:00 colin5514
If the equation;
(3x)² + {27 × (3)^1/k - 15}x + 4 = 0
has equal roots find k
Answers: 2
Another question on Mathematics
Mathematics, 21.06.2019 17:30
Sheila wants to bake six muffins but the recipe is for 12 muffins . this means you only need half of the ingredients listed how much of the of each ingredient does she need? one cup and banana chips ,7 tablespoons oil , two eggs, 3/4 cups flour 1/4 cup walnuts show all you work and justify your answer using a baby toulmin.
Answers: 3
Mathematics, 21.06.2019 19:00
Identify the conclusion of the conditional statement. if you live in phoenix, then you live in arizona.
Answers: 1
You know the right answer?
Questions
Computers and Technology, 28.08.2021 01:00
Chemistry, 28.08.2021 01:00
Chemistry, 28.08.2021 01:00
Chemistry, 28.08.2021 01:00
Mathematics, 28.08.2021 01:00
History, 28.08.2021 01:00
