The curve y=x^2-4x+3 has a gradient of -1 at the point where x=a. Find the value of a.

Step-by-step explanation:

given curve y= x^2-4x+3

differentiate wrt x to get gradient,

dy/dx = 2x-4

2a-4= -1

a= 3/2

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

$12. that is my answer.