If f(x)=(x^2 - 3)^4, then f'(1) = ?

f(1) = 16

Step-by-step explanation:

Substitute x = 1 into f(x) , that is

f(1) =

     =

     =

    = 16

16

f(x) = (x² - 3)⁴

f(1) = (1² - 3)⁴

f(1) = (-2)⁴

f(1) = (-2 × (-2) × (-2) × (-2))

f(1) = (-4 × (-2) × (-2))

f(1) = (-8 × (-2))

f(1) = 16

If f(x) = (x² - 3)⁴ then f(1) is 16.

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet