The point (3,4) is on the graph of y=f(x). State the coordinates of the image of this point on each graph. A)y=f(2x)
b)y=f(0.5x)
c)y=f(t/3x)
d)y=f(-4x)

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

lol 2

step-by-step explanation:

if im not mistaking its

step-by-step explanation:  

i have no clue what you just said. write a question in english?