Can one of you unhelpful users answer the question without putting links as a d a m n answer? 1. A line goes through the points (1, 6) and (–2, 8). Write the equation of the line in Point-Slope form. Show your work algebraically for full credit.

2. A line goes through the points (1, 6) and (–2, 8). Write the equation of the line in Slope-intercept form. Show your work algebraically for full credit. Hint: this is the same line as in #1.

1) and 2)

Step-by-step explanation:

Ikr the bots are annoying.

Point-slope form is written as:

Slope intercept form is written as:

We also need to find the slope before putting it in this form, which can be done by

1) Points given are (1,6) and (-2,8)

Slope:

You can choose either of the two points to put into the formula. I just chose (1,6)

2) Same points as before and we have the same slope as before. All we need is to find the y intercept which is our b in the equation. You can easily do this by plugging in a point and solving for b. I will choose point (1,6) again.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)