PLS HEL Which expression is equivalent to 4−a−a−a?

 " 4 − 3a " .

Step-by-step explanation:

" 4 − a − a − a " ;

        = 4 − 1a − 1a − 1a " ;

        =  ?  " ;

Combine the "like terms" :

         →   " − 1a − 1a − 1a " ;

               = (− 1a − 1a) − 1a ;

               = ( − 2a) − 1a ;

               =  − 3a ;

Now, bring down the "4" ;

  and rewrite the expression:

        →  " 4 − 3a " ;

which cannot be simplified further.

The answer is:  " 4 − 3a " .

Hope this is helpful!

 Best wishes to you!

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

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step-by-step explanation: