Paul has three​ cube-shaped boxes. Each box is a different size and they are stacked from the largest to the smallest. Some information about the boxes is given below. Answer questions 15 below. The combined volume of the three boxes is​ 1,197 cubic inches.

The area of one face of the medium box is 49 square inches.

The volume of the smallest box is 218 cubic inches less than the volume of the medium box.

1. What is the volume of the medium​ box? Explain.

The edge length of the medium box is

â–Ľ

StartFraction StartRoot 49 EndRoot Over 2 EndFraction comma

StartRoot 49 EndRoot comma

RootIndex 3 StartRoot 49 EndRoot comma

StartFraction 49 Over 2 EndFraction comma

which equals

nothing. The volume of the box is the edge length

â–Ľ

squared,

doubled,

tripled,

cubed,

which equals

nothing

â–Ľ

cubic inch(es).

inch(es).

square inch(es).

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation:

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation:

there are infinitely many solutions.