How to put y=14x-62 in standard form, pls explain.

14x - y = 62

Step-by-step explanation:

Hi there!

We are given the equation y=14x-62 and we want to put it into standard form.

Standard form is ax + by = c, where a, b, and c are free integer coefficients, but a and b cannot be equal to zero, and a cannot be negative

The equation is currently in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

Since standard form has the term with x in it on the left side, we can move 14x to the left side (subtract 14x from both sides)

y = 14x-62

-14x -14x

-14x + y = -62

Remember that a (coefficient of x) cannot be negative. So multiply everything by -1 to change the sign of all the terms

-1(-14x + y) = -1(-62)

14x - y = 62

Hope this helps!

step-by-step explanation:

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>