1) Factorise 3x^2 + 5x + 2
2) Hence, solve x^2 + 5x + 2

(x+1)(3x+2) , i only got the answer for the first question, sorry!

Step-by-step explanation:

- factorise using AC method

AC= 3 x 2 = 6

find 2 numbers that add to give 5 and multiply to give 6 (3 and 2)

- put them as x in the equation to replace 5x

3x^2 + 2x + 3x + 2

- split the equation in half and expand each side

3x^2+2x | 3x+2

x(3x+2)+1(3x+2)

- put the numbers outside the brackets into a separate bracket

= (x+1)(3x+2)

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752