PLEASE HELP ME WITH IT

B     n-12  turns into 12 which makes 7n-5 become -1 +7- 5 = 1

as 12 x7 = 84 and -5 + 84 = 79 our end sequence.

Step-by-step explanation:

how to approach answering questions for hw and for exam

step 1 hw  find a diagram   exam rewrite the diagram

step 2 hw work out each multiple question

step 3 see below how workings should be

SIGMA TELLS US     The nth term is  = k

SIGMA TELLS US      The bottom value is value we start with    _vs

SIGMA TELLS US      The top value is the term we end with      - te

A     n-2  turns into 9  which makes  7n-5    become -2+7-5 = 0  

B     n-12  turns into 12 which makes 7n-5 become -1 +7- 5 = 1   (12 x7=84 and -5+84 = 79)

we can prove by using nth common term 7 x 12 -5 = 79

C     n -1   turns into 5 which becomes -1+7 = 6

D     n- 1 turns into 5 which becomes -1+7-5 = 1

we see the sequence given is 2, 9, 16 ....79  it is ascending sequence +7

we know the nth term is 7n-5 as we work out first step ( 2 - 7= -5)

we see the term we end with is either 9 12 or 5 and we see the end term given value is 72 so B is our answer.

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

i got 10.28 but that rounds up to 10.3