Work out the area of a rectangle with base,
b
= 16mm and perimeter,
P
= 52mm.

A = 160 mm²

Step-by-step explanation:

The area (A) of a rectangle is calculated as

A = bh ( b is the base and h the height )

Given P = 52 and P = 2(b + h) , then

2(b + h) = 52 ( divide both sides by 2 )

b + h = 26 ( substitute b = 16 )

16 + h = 26 ( subtract 16 from both sides )

h = 10

Then

A = 16 × 10 = 160 mm²

its: 160^{2}

Step-by-step explanation:

ps: (b=l)

we have  : P=2 [l+w]

and : P= 52mm

so: 52=2(16mm+w)

    52/2= 16mm+w

     26-16=w

   10=w

so: w=10

and we know that:  area= w*l

so:                          area=10*16

so:          area= 160 mm^{2}

8496 cars

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet