1. Daniel and his friends are at an outdoor concert. They were close to the stage and it was too loud. They moved back so that they were a distance 6 times further away. By how much did the sound level decrease when Daniel and his friends moved away from the source of the sound? 1 How much the intensity of sound decreases with increasing relative distance from a source can be found with this expression: or d-?. Use this distance. distance relationship to calculate how much the sound level decreased and complete the statement below, of what it When Daniel and his friends moved back 6 times further away from the source of the sound, the sound level was approximately was when they were closer

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt

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