Square abcd has vertices at A(-5,-3) and B(-4,4). find the slope of each side. Slope of AB=

Slope of BC=

Slope of CD=

Slope of DA=

Also explain how you got your answer bc my test is in two days and i truly dont understand. brainliest goes to best explained

answer: -1

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

47 - 90 = 43

43 - 180 = x

x = 137

ask the math teacher she or he would know lol.

step-by-step explanation: