Please help this question..

Step-by-step explanation:

2).

Given that 1/(7+5√2)

We know that

The Rationalising factor of a+√b is a-√b

The denominator = 7+5√2

The Rationalising factor of 7+5√2 is 7-5√2

On Rationalising the denominator then

=> [1/(7+5√2)]×[ (7-5√2)/(7-5√2)]

=> [1×(7-5√2)]/(7+5√2)(7-5√2)]

=> (7-5√2)/[(7+5√2)(7-5√2)]

=> (7-5√2)/[7²-(5√2)²]

Since , (a+b)(a-b) = a²-b²

Where , a = 7 and b = 5√2

=> (7-5√2)/(49-50)

=> (7-5√2)/(-1)

=> -7+5√2

=> 5√2-7

3).

Given that (x-2)³

This is in the form of (a-b)³

Where, a = x and b = 2

We know that

(a-b)³ = a³-3a²b+3ab²-b³

=> (x-2)³ = x³-3(x²)(2)+3(x)(2)²-2³

=> (x-2)³ = x³-6x²+12x-8

The coefficient of x² is -6

step-by-step explanation:

i could only see the first page. the other pages were blurry. ; -;

x hot dogs for 2$, y drinks for 3$. 29 items and total 70

2x+3y=70

x+y=29

if x=17and y=12

2(17)+3(12)=70

34+36=70

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )