A scuba diver descends in the water at a rate of 20 1/2 feet per minute for 2.8 minutes. He immediately changes course when he sees a large fish and ascends at a rate of 25 feet per minute for 2 minutes. What is the scuba diver's position relative to sea level after the 4.8 minutes?

Step-by-step explanation:

Assumed the starting point is the sea level 0.

After 2.8 min the diver is at position:

The position change after next 2 minutes:

The position of the diver after 4.8 min:

7.4 feet under sea level

Step-by-step explanation:

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step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)