A long jumper leaves the ground at an angle of 22 above the horizontal, at a speed of 10 m/s. The height of the jumper can be modeled by (x) = -0.048x²+0.365x, where his the jumper's height in meters and X is the horizontal distance from the point of

launch

Part: 0/3

Part 1 of 3

(a) At what horizontal distance from the point of launch does the maximum height occur? Round to 2 decimal places.

The long Jumper reaches a maximum helght when the horizontal distance from the point of

launch is approximately meters

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m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right

let f (x ) is a function and c be a positive real number,   the graph of the function g (x ) = f (cx ) is represented as follows.

when, c > 1,   the function compresses it in the x - direction.

when, 0 < c < 1, the function stretches it.

the function is g ( x ) = (9x )2.

the heighest power of x in g ( x ) = (9x )2 is 2, so the parent function is square function.

the equation of parent function is f ( x ) = x 2 .

the function is g ( x ) = (9x )2 and the parent function is f ( x ) = x 2 .

so, the functions f and g have the following relationship.

g ( x ) = f ( 9x ).

compare the function g ( x ) = f ( 9x ) with g (x ) = f (cx ).

c = 9 ( > 1 ).

so, the function g (x ) = (9x )2 compresses it in the x - direction.

step-by-step explanation:

the answer to this in exact form is 4/35 but in decimal form its 0.1142857

hope this if needed hmu