Consider the parabola given by the equation: y = 1x^2 - 12x + 27 A) the vertex = (_,_)

B) the y-intercept is the point (0,_)

C) find the two values of x that corresponds to the x intercepts of the parabola and write them as a list separated by commas:
X= ___

vertex: (6, -9)

y intercept: (0, 27)

X = 3, 9

Step-by-step explanation:

Finding Vertex (Part A)

Consider the formula -b/2a. This formula gives you the x-coordinate of the vertex.

y = 1x^2 - 12x + 27

a = 1

b= -12

c =27

-b/2a = - (-12)/2(1) = 12/2 = 6 (x-coordinate of vertex)

When solving for the y-coordinate of the vertex you will need to substitute your 'x" back into the equation.

y = 1(6)^2 - 12(6) + 27

y = 36 - 72 + 27 = -9 (y-coordinate of vertex)

Y- Intercept (Part B)

When looking for the y-intercept your "x" must always be 0.

Substitute 0 in every "x" in equation.

y = 1(0)^2 - 12(0) + 27

y = 27

y intercept: (0, 27)

X- Intercepts (Part C)

To find the values of "x" factor.

y = 1x^2 - 12x + 27

0 = 1x^2 - 12x + 27

0 = (x  - 3     )(x   -  9 )

(x-3) = 0             (x-9) = 0

x = 3                    x = 9

a=r

d=q

c=p

b=s

hope this !

yes

step-by-step explanation: