Solve 6x + c = k for x. O A. x-kit
X
K+C
6
O B. x = 6(k - c)
C.
X =
-c
x 86
O D. X = 6(k+c)

x = (k - c)/6

Step-by-step explanation:

6x + c = k

First, subtract c from both sides.

6x = k - c

Then, divide by 6 on both sides.

x = (k - c)/6

your answer is a

step-by-step explanation:

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option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.