Describe the graph of the quadratic function: f(x) = 5(x - 3)2 + 2. (A)Opens downward and has maximum value at (3, 2) (B)Opens upward and has minimum value at (3, 2) (C)Opens downward and has minimum value at (3, 2) (D)( Opens upward and has maximum value at (3, 2)

Given the quadratic function, f(x) = 5(x - 3)^2 + 2, where:

a = 5 = determines whether the parabola opens upward (positive value) or downward (negative); also how wide or narrow the graph.

(h, k) = (3, 2) = vertex

In your given function, a = 5, which means the graph opens upward, and the vertex (3, 2) is the MINIMUM VALUE.

Therefore, the correct answer is B.

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