Assume that the playbook contains 9 passing plays and 15 running plays. the coach randomly selects 8 plays from the playbook. what is the probability that the coach selects at least 2 passing plays and at least 3 running plays?

Answer = probability that he selects exactly 2,3,4 or 5 passing plays. prob that he selects exactly two passing plays = (8C2)*(9*8)* (15*14*13*12*11*10) /(26*28*19) where: 8C2 is the number of ways of choosing two slots out of 8 and prob that he selects first passing play = 9/26 prob that he select second passing play = 10/25 etc you can calculate the other three cases similarly and sum to obtain the answer.

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