Find the x and y intercepts for the equation 5x+3y=30

x-intercept = (6, 0)

y-intercept = (0, 10)

Step-by-step explanation:

Given the linear equation, 5x + 3y = 30:

We can find the y-intercept by setting x = 0, because the y-intercept is the y-coordinate of the point (0, b) where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0.

Y-intercept: let x = 0:

5x + 3y = 30

5(0) + 3y = 30

0 + 3y = 30

Divide both sides by 3 to solve for y:

3y/3 = 30/3

y = 10

Therefore, the y-intercept = (0, 10).

The x-intercept is the point (a, 0) on the graph where it crosses the x-axis.  It is also the value of x when y = 0.

X-intercept: let y = 0:

5x + 3(0) = 30

5x + 0 = 30

5x = 30

Divide both sides by 5 to solve for x:

5x/5 = 30/5

x = 6

Therefore, the x-intercept = (6, 0).

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X-intercept = (6,0)

Y-intercept = ( 0,10)

Step-by-step explanation:

To find the x-intercept, substitute in  0  for  y  and solve for  x

5x + 3(0) = 30                 Since solving for Y when writing it 0 is in the y place

5x + 0 = 30

5x = 30

5x/5 = 30/5

x = 6

To find the y-intercept, substitute in  0  for  x  and solve for  y. Since solving for x when writing it 0 goes in the place of the y place

5x + 3y = 30  

5(0) + 3y = 30

0 + 3y = 30

3y/3 = 30/3

Y - Intercept = (0,10)

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