Help please? I’m not sure what to do??? A student has scores of 76.5, 79, and 81.75 on his first three tests. He needs an average of at least 80 to earn a grade of B. What is the minimum score that the student needs on the fourth test to ensure a B?

82.75 is the correct answer

Step-by-step explanation:

76.5 + 79 + 81.75 + 82.75 = 320

320 / 4 = 80

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

yes

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step-by-step explanation: