Mathematics, 17.10.2021 09:00 mmcdaniels46867

How many squares of side 5 cm are required to cover a rectangle measuring 35 cm by 20 cm?

Answers: 1

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Answers

In order to figure out how many squares will fit inside the rectangle, we can calculate the area of the square and rectangle first.

1.) Area of a square:
A=s^2
A=(5)^2
A=25cm^2.
The area of the square is 25cm^2.

2.) Area of the rectangle:
A=L•W
A=(35)•(20)
A=700cm^2.
Therefore, the area of the rectangle is 700cm^2.

Now, we must create an Algebraic equation to figure out how many times the area of the square will fit into the area of the rectangle.

4.) 25X=700.
25X/25=700/25
X=28

We know one square with side lengths of 5 is 25, and we are trying to figure out how many times the area of the square will equally fit into the area of the rectangle. X=factor of how many the area of the square is multiplied to total the area of the rectangle.

Therefore, the square will fit into the rectangle 28 times, so there are 28 squares with the same dimensions that will fit into the rectangle.

Answer from: davilynealvarado1234

28 squares of 5cm x 5 cm (25cm^ each)

Step-by-step explanation:

35/5 = 7 sides measuring 5 cm each. (Length divided in 7)

20/5 = 4 sides measuring 5 cm each (width divided in 4)

7 x 4 = 28 squares of 5 x 5

Answer from: Quest

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2 polynomial long division

dividing : x4+5x3-4x2-8x+6

("dividend")

by : x-1 ("divisor")

dividend x4 + 5x3 - 4x2 - 8x + 6

- divisor * x3 x4 - x3

remainder 6x3 - 4x2 - 8x + 6

- divisor * 6x2 6x3 - 6x2

remainder 2x2 - 8x + 6

- divisor * 2x1 2x2 - 2x

remainder - 6x + 6

- divisor * -6x0 - 6x + 6

remainder 0

quotient : x3+6x2+2x-6 remainder: 0

Answer from: Quest

idk lol xd

step-by-step explanation:

ez do it yourself lazy

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