What is an equation of the line that passes through the points (0,8) and (-8,-4)

Using the given points, find the slope:

 Slope Equation: m = Δy/Δx

 m = (4 - 0)/(8 -(-8)) ⇒ Solve

 m = 4/16 ⇒ Simplify

 m = 1/4

Using the point-slope equation, solve for the line:

 Point-Slope Equation: y - y1 = m (x - x1)

 Using Point 1 (-8, 0):

 y - 0 = 1/4 (x - (-8))

 y - 0 = 1/4 (x + 8) ⇒ Distribute

 y = 1/4x + 8/4 ⇒ Simplify

 y = 1/4x + 2

y = 1/4x + 2

First finding the slope and the y-intercept. Then we can write the equation in slope-intercept for which is

y = mx+b where m is the slope and b is the y-intercept.

Given two points (0,8) and (-8,-4). (0,8) is the y intercept which is the value of b. Since we have found the y-intercept, To find slope of these two points.

m = (y2-y1)/(x2-x1)

m = (-4-8)/(-8-0)

m = (-12)/(-8)

m = 12/8

m = 3/2

So, the equation is y = 3/2(x)+8 and has been fully reduced.

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