Using the substitution method Ken solves the following system of equations algebraically 2x-y=5
3x+2y=-3

which equivalent equation could ken us

a 3x+2 (2x-5)=-3)
b 3 (y+5/2) +2y=-3
c 3+2( 5-2x)=-3
d 3 5/2-y) +2y=-3

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions