(5x^4-3x^3+2)-(-3x^4+2x^2-5)

Here's the solution :

8-3-2+7

Step-by-step explanation:

The first thing to do in this problem is distribute the negative in front of (). This makes it .

From here you can remove the parenthesis and combine like terms. 5 combines with 3 to get 8 and 2 and 5 combine to get 7. The -3 and -2 cannot combine with anything since they don't share any like terms.

Using the combinations, bring all of the terms back together and you get 8-3-2+7

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.