Write the equation of the line in standard form that passes through (-1, 3) and (2, 9). }

y = 2x + 5

Step-by-step explanation:

(-1 , 3) & (2 , 9)

x₁ = -1  ; y₁ = 3    & x₂ = 2 ; y₂ = 9

m = 2 & (-1 , 3)

Equation of line:

y - y₁ = m(x - x₁)

y - 3 = 2(x - [-1])

y -3 = 2(x + 1)

y - 3 =2x +2

y = 2x + 2 + 3

y = 2x + 5

what the question so we can you out

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0