subject
Mathematics, 19.10.2021 14:00 2Pallie2

What is the stopping distance for a vehicle traveling at 20 mph? QuadReg

y=ax2+bx+c

a=.0473809524

b= 2.221428571

C=-.005952381

R? =. 9999956228

o 20 ft

063.4ft

45.36 ft

126.4 ft

Ginish

ansver
Answers: 2

Another question on Mathematics

question
Mathematics, 21.06.2019 14:30
Bismuth-210 is an isotope that radioactively decays by about 13% each day, meaning 13% of the remaining bismuth-210 transforms into another atom (polonium-210 in this case) each day. if you begin with 233 mg of bismuth-210, how much remains after 8 days?
Answers: 3
question
Mathematics, 21.06.2019 23:30
Segment wx is shown explain how you would construct a perpendicular bisector of wx using a compass and a straightedge
Answers: 1
question
Mathematics, 22.06.2019 00:30
What should be done to both sides of the equation in order to solve -5m = -40? a) multiply by -5. b) divide by -5. c) multiply by -40. d) divide by -40.
Answers: 2
question
Mathematics, 22.06.2019 00:50
Melissa is purchasing a $160,000 home and her bank is offering her a 30-year mortgage at a 4.9% interest rate. in order to lower her monthly payment, melissa will make a 20% down payment and will purchase 3 points. what will her monthly mortgage payment be? a. $645.98 b. $650.46 c. $662.93 d. $606.69
Answers: 2
You know the right answer?
What is the stopping distance for a vehicle traveling at 20 mph? QuadReg

y=ax2+bx+c
Questions
question
Mathematics, 15.10.2019 22:40
Questions on the website: 13722363