The line through (-2, 3) with slope 2/3 in point slope form

y - 3 = 2/3(x + 2)

Step-by-step explanation:

slope = 2/3

point-slope form --> y - y1 = m(x - x1)

y - 3 = 2/3(x - -2)

y - 3 = 2/3(x + 2)

point slope form of the line is y - 3 = 2/3(x + 2)

y - 3 = 2/3(x + 2)

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )