A college has two classrooms of students. • Classroom A had 70 students.
• Classroom B had 30 students.
• Classroom A sent groups of 4 students to Classroom B until both classrooms had the same number
of students.
The equation shown can be used to find the number of groups that Classroom A sent to Classroom B so
each classroom had the same number of students.
70 - 4x = 30 + 4x
How many groups did Classroom A send to Classroom B?

20

Step-by-step explanation:

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

one set of data has more variation than the other. hope this !