Please help with this question!

D

Step-by-step explanation:

When the ball hits the ground then h = 0 , that is

- 5t² + 13t + 6 = 0 ( multiply through by - 1 )

5t² - 13t - 6 = 0

Consider the factors of the product of the coefficient of the h² term and the constant term which sum to give the coefficient of the h- term.

product = 5 × - 6 = - 30 and sum = - 13

The factors are - 15 and + 2

Use these factors to split the h- term

5t² - 15t + 2t - 6 = 0 ( factor the first/second and third/fourth terms )

5t(t - 3) + 2(t - 3) = 0 ← factor out (t - 3) from each term

(t - 3)(5t + 2) = 0

Equate each factor to zero and solve for t

t - 3 = 0 ⇒ t = 3

5t + 2 = 0 ⇒ 5t = - 2 ⇒ t = -

Now t > 0 , so t= 3

The ball hits the ground after 3 seconds

mx+89b(-98)nb

step-by-step explanation:

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²